SAT Math lug‘ati
Inglizcha atama yoki o‘zbekcha tarjima bo‘yicha qidiring.
23 ta natija
exceeds
dan oshadi / dan katta
x = y + 7
Matnli masala tiliboshlang‘ichis greater than
dan katta
3x > 12
Matnli masala tiliboshlang‘ichis less than
dan kichik
n < 9
Matnli masala tiliboshlang‘ich4 less than twice b
b ning ikki baravaridan 4 taga kam
a = 2b − 4
Matnli masala tilio‘rtais at least
kamida
x ≥ 12
Matnli masala tiliboshlang‘ichis at most
ko‘pi bilan
n ≤ 20
Matnli masala tiliboshlang‘ichno more than
dan ko‘p emas
w ≤ 50
Matnli masala tilio‘rtano less than
dan kam emas
T ≥ 30
Matnli masala tilio‘rtais less than or equal to
dan kichik yoki teng
c ≤ 80
Matnli masala tiliboshlang‘ichtwice as much as
… ning ikki baravari
M = 2K
Matnli masala tiliboshlang‘ichhalf of
… ning yarmi
s/2
Matnli masala tiliboshlang‘ichthe difference between
… orasidagi ayirma
x − 5 = 12
Matnli masala tiliboshlang‘ichthe sum of
… ning yig‘indisi
n + (n + 1) = 41
Matnli masala tiliboshlang‘ichthe product of
… ning ko‘paytmasi
4x = 28
Matnli masala tiliboshlang‘ichthe quotient of
… ning bo‘linmasi
y/3 = 7
Matnli masala tilio‘rtaincreased by
… ga oshirildi
x + 6 = 20
Matnli masala tiliboshlang‘ichdecreased by
… ga kamaytirildi
x − 8 = 15
Matnli masala tiliboshlang‘ichconsecutive integers
ketma-ket butun sonlar
n + (n+1) + (n+2) = 72
Matnli masala tilio‘rtain terms of x
x orqali (ifodalang)
y = 10 − 3x
Matnli masala tilio‘rtarespectively
mos ravishda
p = 2, n = 4
Matnli masala tilio‘rtathe remaining amount
qolgan miqdor
60 − x = 18
Matnli masala tiliboshlang‘ichthe quantity
… ifoda (qavs ichida)
5(x − 1) = 20
Matnli masala tilio‘rtathe greatest possible value
eng katta mumkin bo‘lgan qiymat
x ≤ 6 ⇒ 6
Matnli masala tilio‘rta